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As the lines are perpendicular, Coefficient of `x^(2)+` Coefficient of `y^(2)=0` <br> `:.a-2=0` <br> or `a=2` <br> Also , `abc+2fgh-af^(2)-bg^(2)-ch^(2)=0` <br> `:. c=-3` <br> Hence , the given pair of lines is <br> `2x^(2)+3xy-2y^(2)-5x+5y-3=0` <br> Factorizing , we get lines <br> `x+2y-3=0and 2x-y+1=0` <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CEN_CG_C03_E05_005_S01.png" width="80%"> <br> The point of intersection of the lines is C `(1//5,7//5)`. <br> The points of intersection of the lines with the x- axis are A(3,0) and B `(-1//2,0)`. <br> The orthocenter of triangle is C `(1//5,7//5)` and the circumcenter is the midpoint of AB which is M `(5//4,0)`. Therefore, <br> CM`sqrt(((5)/(4)-(1)/(5))^(2)+(49)/(25))=(7)/(4)`**Explain Pair of straight lines with examples.**

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